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Unsolved: solve[ad^-1 LambertW[ad ln[2]] === ex2 x^-2 ln[2], ad]

Solution:

x = xsq1

x = - ⁢ xsq1

x = ad ⁢ ex2 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

x = - ⁢ ad ⁢ ex2 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

x = - ⁢ ex2 e ⁢ LambertW ⁡ [ - 1 e ]

x = - ⁢ - ⁢ ex2 e ⁢ LambertW ⁡ [ - 1 e ]

x = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ] - digits ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ]

x = - ⁢ - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ] - digits ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ]

x = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ] - tprime ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ]

x = - ⁢ - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ] - tprime ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ]

x = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] - digits ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

x = - ⁢ - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] - digits ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

x = 3 ⁢ ad ⁢ e ⁢ ln ⁡ [ 2 ] 2 LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] + ad ⁢ digits ⁢ e ⁢ ln ⁡ [ 2 ] ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

x = - ⁢ 3 ⁢ ad ⁢ e ⁢ ln ⁡ [ 2 ] 2 LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] + ad ⁢ digits ⁢ e ⁢ ln ⁡ [ 2 ] ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

x = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] - tprime ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

x = - ⁢ - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] - tprime ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

tprime = digits ⁢ ln ⁡ [ 10 ] ln ⁡ [ 2 ]

tprime = - 3 - ad ⁢ ex2

tprime = - 3 + ex2 e ⁢ ln ⁡ [ 2 ]

tprime = - 3 - x 2 ⁢ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ln ⁡ [ 2 ]

tprime = - 3 - xsq1 ⁢ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ln ⁡ [ 2 ]

ex2 = x 2 ⁢ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ad ⁢ ln ⁡ [ 2 ]

ex2 = - 3 ad - digits ⁢ ln ⁡ [ 10 ] ad ⁢ ln ⁡ [ 2 ]

ex2 = - ⁢ e ⁢ x 2 ⁢ LambertW ⁡ [ - 1 e ]

ex2 = xsq1 ⁢ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ad ⁢ ln ⁡ [ 2 ]

ex2 = 3 ⁢ e ⁢ ln ⁡ [ 2 ] + digits ⁢ e ⁢ ln ⁡ [ 10 ]

ex2 = - 3 ad - tprime ad

xsq1 = x 2

xsq1 = ad ⁢ ex2 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

xsq1 = - ⁢ ex2 e ⁢ LambertW ⁡ [ - 1 e ]

xsq1 = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ] - digits ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ]

xsq1 = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ] - tprime ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ]

xsq1 = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] - digits ⁢ ln ⁡ [ 10 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

xsq1 = - 3 ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] - tprime ⁢ ln ⁡ [ 2 ] LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ]

ad = - 1 e ⁢ ln ⁡ [ 2 ]

solve ⁡ [ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ad === ex2 ⁢ ln ⁡ [ 2 ] x 2 , ad ]

ad = - 3 ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ⁢ ln ⁡ [ 2 ]

solve ⁡ [ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ad === ex2 ⁢ ln ⁡ [ 2 ] xsq1 , ad ]

ad = - 3 ex2 - tprime ex2

digits = tprime ⁢ ln ⁡ [ 2 ] ln ⁡ [ 10 ]

digits = - 3 ⁢ ln ⁡ [ 2 ] ln ⁡ [ 10 ] - ad ⁢ ex2 ⁢ ln ⁡ [ 2 ] ln ⁡ [ 10 ]

digits = ex2 e ⁢ ln ⁡ [ 10 ] - 3 ⁢ ln ⁡ [ 2 ] ln ⁡ [ 10 ]

digits = - x 2 ⁢ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ln ⁡ [ 10 ] - 3 ⁢ ln ⁡ [ 2 ] ln ⁡ [ 10 ]

digits = - xsq1 ⁢ LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ln ⁡ [ 10 ] - 3 ⁢ ln ⁡ [ 2 ] ln ⁡ [ 10 ]

e = LambertW ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ad ⁢ ln ⁡ [ 2 ]

e = LambertW1 ⁡ [ ad ⁢ ln ⁡ [ 2 ] ] ad ⁢ ln ⁡ [ 2 ]

e = LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ] ln ⁡ [ 2 ] ⁢ ( - 3 ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ⁢ ln ⁡ [ 2 ] )

e = LambertW1 ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ] ln ⁡ [ 2 ] ⁢ ( - 3 ex2 - digits ⁢ ln ⁡ [ 10 ] ex2 ⁢ ln ⁡ [ 2 ] )

e = LambertW ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ] ( - 3 ex2 - tprime ex2 ) ⁢ ln ⁡ [ 2 ]

e = LambertW1 ⁡ [ - 3 ⁢ ln ⁡ [ 2 ] ex2 - tprime ⁢ ln ⁡ [ 2 ] ex2 ] ( - 3 ex2 - tprime ex2 ) ⁢ ln ⁡ [ 2 ]


Evaluated result:

SymSymbolic?Value
ad =
digits =
e =
ex2 =
tprime =
x =
xsq1 =

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xsq1 = x 2
     = 26.01

ad = - 1 e ⁢ ln ⁡ [ 2 ]
   = - 0.36787944117144232159 ln ⁡ [ 2 ]
   = - 0.53073784542304299574

48 items suppressed because of above options.

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View source of this FSP page or the transformation rules that solve these equations.

Alan Eliasen, eliasen@mindspring.com

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