Solution:
z === 4 arctan[1/10 - 7/5 sin[x]2] x === arcsin[(1/14 - 5/7 tan[1/4 z])^(1/2)] x === arcsin[-1 (1/14 - 5/7 tan[1/4 z])^(1/2)]
Evaluated result:
z = 4 arctan[1/10 - 7/5 sin[x]2] x = arcsin[(1/14 - 5/7 tan[1/4 z])^(1/2)] x = arcsin[-1 (1/14 - 5/7 tan[1/4 z])^(1/2)]
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